[ADMB Users] df1b2variable/prevariable operator
mbrooks at ufl.edu
Mon Jul 11 10:48:41 PDT 2011
There seems to be no operator defined for dividing a df1b2variable by a prevariable. Should I create a new df1b2variable and set it equal to the prevariable denominator?
Will this operator eventially get defined? Should I add it as a feature request?
This is the function I'm trying to write:
df1b2variable Michaelis_Menten1(const double& x, const df1b2variable& a, const prevariable& b)
When I try to use it, I get the following error
In function 'df1b2variable Michaelis_Menten1(const double&, const df1b2variable&, const prevariable&)':
./Michaelis_Menten1.cpp:62: error: no match for 'operator/' in 'operator*(const df1b2variable&, double)(x) / operator+(((const prevariable&)((const prevariable*)b)), x)
I believe the relevant candidates are:
df1b2variable operator/(double, const df1b2variable&)
df1b2variable operator/(const df1b2variable&, double)
df1b2variable operator/(const df1b2variable&, const df1b2variable&)
More information about the Users